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x^2+8.04x-3.245=0
a = 1; b = 8.04; c = -3.245;
Δ = b2-4ac
Δ = 8.042-4·1·(-3.245)
Δ = 77.6216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.04)-\sqrt{77.6216}}{2*1}=\frac{-8.04-\sqrt{77.6216}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.04)+\sqrt{77.6216}}{2*1}=\frac{-8.04+\sqrt{77.6216}}{2} $
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